Right way to do a 4 value per cell heatmap

[BenoitFiset]

Hi,

Trying to figure out a right way with the package to create a heatmap that each cell has 4 different colour coded values. The values come from 4 different matrices.

Something like this - which would be the first 2 cells (each 4x4 is 1 cell) of a heatmap (Copy this multiple rows and columns in your mind to make the whole heatmap)

M1-M2-M3-M4 = are the colour codes values from the 4 different matrices
The 1-2 are the values in the position of the matrices: 1 would be [1,1] and 2 would be [1,2] and so on...

I was wondering if there is a function in the package to cut up a cell in 4 values or I would just "statically" create row by row and column by column and use row_split/column_split to make my own slices ? Or there is a way to use functions to modify OncoPrint to do this ?

Moving up a notch, with 3D heatmap function, would it be possible to do a 3D stacked chart plot like superposing differently coloured blocks at each cell position ? (I know people usually don't like 3D plots... but just asking :) )

Thanks for suggestions.

[jokergoo]

Are you using the general Heatmap() function or the specific oncoPrint() function? Basically you can self-define any graphics in cells by cell_fun or alter_fun.

For 3D heatmap, the 3D functionality was implemented only for fun and I am not planning to support it with more features.

[BenoitFiset]

Hi,

I was using Heatmap(). So what you are writing is that I can make 4 different squares with 4 different data points in one cell of the heatmap() with cell_fun / alter_fun ?

[jokergoo]

I can give you an example here:

m = matrix(rnorm(100), 10)

Heatmap(m, layer_fun = function(j, i, x, y, w, h, f) {
    grid.rect(x, y, width = w*0.5, height = h*0.5, just = c("left", "bottom"))
    grid.rect(x, y, width = w*0.5, height = h*0.5, just = c("left", "top"))
    grid.rect(x, y, width = w*0.5, height = h*0.5, just = c("right", "bottom"))
    grid.rect(x, y, width = w*0.5, height = h*0.5, just = c("right", "top"))

    grid.text("1", x = x - w*0.25, y = y - h*0.25)
    grid.text("2", x = x - w*0.25, y = y + h*0.25)
    grid.text("3", x = x + w*0.25, y = y - h*0.25)
    grid.text("4", x = x + w*0.25, y = y + h*0.25)
})